Use

newrate[[i]] <- read.csv(rates[i])

better yet, use a list and lapply

newrate <- lapply(paste('rate', 1:4, '.csv', sep=''), read.csv)

On Sat, Dec 26, 2009 at 8:09 AM, Maithili Shiva <maithili_shiva@yahoo.com>wrote:

> Dear R helpers / Johannes Sir,
>
> Unfortunately it didn't work.
>
> I am getting following warning messages.
>
> 1: In neweate[i] = read.csv(rates[i]) :
>   number of items to replace is not a multiple of replacement length.
> 2:  similar message
> 3:  similar message
> 4: similar message
>
> Let me be specific in my problem.
>
> I have three csv files as
>
> rate1.csv
> r1        r2        r3        r4        r5         r6
> 10.1   10.25   10.25   10.50   10.50    10.75
>
> rate2.csv
> r1        r2        r3        r4        r5         r6
> 15.1   15.45   15.45   15.70   15.70    15.90
>
> rate3.csv
> r1        r2        r3        r4        r5         r6
> 18.3   18.50   18.50   18.65   18.65    18.95
>
> Normally I can read these files as
>
> newrate1  =  read.csv('rate1.csv'')
> newrate2  =  read.csv('rate2.csv')
> newrate3  =  read.csv('rate3.csv')
>
> However, due to some other requirement first I have to define following R
> code
>
> n = 3
>
> rate_name = NULL
>
> for (i in 1:n)
>
> rate_name[i] = (paste(`rate', i, С.csv`, sep = СТ))
>
> # rate_name gives "rate1.csv" "rate2.csv" "ratы3.csv"
>
>
> ### MY TASK
>
> I need to use the rate_names to read the actual rate1.csv, rate2.csv and
> rate3.csv files.
>
> When I use the following code
>
> newrate <- list()
> for (i in 1:n)
>    {
>     newrate[i] = read.csv(rate_name[i])
>    }
>
> I get following warning messages
>
> 1: In newrate[i] = read.csv(rate_name[i]) :
>   number of items to replace is not a multiple of replacement length
> 2: similar message
> 3: similar message
>
>
> ## APPROACH II
>
> PPP = matrix(data = rate_name, nrow = 1, ncol = 3, byrow = FALSE)
> X = matrix(data = NA, nrow = 3, ncol = 6, byrow = FALSE)
>
> for (j in 1:3)
> X = read.csv(PPP[1, j])
>
> # X returns  (i.e. only first record is taken)
>
> r1        r2        r3        r4        r5         r6
> 10.1   10.25   10.25   10.50   10.50    10.75
>
>
> Please guide
>
> With regards
>
> Maithili
>
>
> --- On Sat, 26/12/09, Johannes Signer <j.m.signer@gmail.com> wrote:
>
>
> From: Johannes Signer <j.m.signer@gmail.com>
> Subject: Re: [R] Reading Input file
> To: "Maithili Shiva" <maithili_shiva@yahoo.com>
> Cc: r-help@r-project.org
> Date: Saturday, 26 December, 2009, 9:42 AM
>
>
>
>
>
> On Sat, Dec 26, 2009 at 10:21 AM, Maithili Shiva <maithili_shiva@yahoo.com>
> wrote:
>
>
>
> Dear R helpers
>
> I have some files in my say 'WORK' directory and the file names are say
> rate1.csv, rate2.csv, rate3.csv, rate4.csv
>
> Because of some other requirement, I need to run the following commands
>
> n = 4
>
> rates = NULL
>
> for (i in 1:n)
>
> rates[i] = (paste(`rate', i, С.csv`, sep = СТ))
>
> # this gives me "rate1.csv" "rate2.csv" and so on
>
> #My problem is now I need to relate these file names with actual files and
> read these files
> # There are files rate1.csv, rate2.csv, rate3.csv, rate4.csv in my WORK
> directory.
>
>
> # If I individually define
>
> PPP = read.csv(Сrate[1]Т)
> PPP      # When I run PPP in R, it gives contents of the file rate1.csv
> i.e. I am able to read the required rate1 file. But if I run following
> commands, I get errors.
>
> newrate = NULL
>
>
> Maybe try:
>
> newrate <- list()
>
> and leave everything else as it is.
>
> just an idea,
>
>
> for (i in 1:n)
>    {
>     newrate[i] = read.csv(rates[i])
>    }
>
> I need to read all these four files for my further analysis. Please guide.
>
>
> Regards
>
> Maithili
>
>
>
>
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>
>
>
>
>
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>
>


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+1 513 646 9390

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