Subodh
Assuming the data is ordered by date then you can define
fin.years = (0:(10*12-1)) %/% 12

then use aggregate:
aggregate(x, list(fin.years),sum)

HTH
Schalk Heunis


On Thu, Sep 17, 2009 at 6:11 PM, Subodh Acharya <shoebodh@gmail.com> wrote:

> Hi everyone,I have a data daily data (x) for 10 years starting from
> 04-01-1995 to 03-31-2005.
> I was able to get the yearly sum for the ten years using
> aggregate(x, years, sum).
> But this gave me the yearly sum for 1995 (Apr- Dec); 1996 (Jan-Dec)
> ---------2005 (Jan-Mar).
> But I want to get the aggregates for Apr-1995 to Mar 1996, Apr 1996- mar
> 1997 and so on.
>
> your help will be higly appreciated.
> Thanks in advance
>
> --
> Acharya, Subodh
>
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