Ding!  We have a winner :)

Thanks Max, that's exactly the problem.  I don't know how I missed that.

I'm looking for different modeling functions to try for best predictive 
results.  An SVM isn't bad, but I'm looking for more.  The RVM sounded 
interesting, but I guess it won't work for my application.

THANK YOU!

-N

On 8/19/09 3:52 PM, Max Kuhn wrote:
> I think that the issue is that this version of rvm is only for 
> regression (and, if I understood correctly, you are passing class 
> labels).
>
> Max
>
>
>
> On Aug 19, 2009, at 6:36 PM, David Winsemius <dwinsemius@comcast.net> 
> wrote:
>
>>
>> On Aug 19, 2009, at 6:30 PM, Noah Silverman wrote:
>>
>>> Thanks David,
>>>
>>> Then, do you have any clue why RVM or LSSVM would be generating an 
>>> error?
>>
>> No.
>>>
>>> My original post was:
>>>
>>>
>>> "When running RVM or LSSVM on the exact same data as the SVM{e1071}, 
>>> I get an error that I don't understand:
>>> Error in .local(x, ...) : kernel must inherit from class 'kernel' "
>>>
>>> Any suggestions?
>>
>> My suggestion would be to include more information. Expecting people 
>> to figure out where the error arose when they have not been given: a) 
>> the code that produced the error and b) a good-faith effort at a 
>> description of the data supplied seems an exercise in futility.
>>
>>
>>>
>>> Thanks!
>>>
>>>
>>>
>>> On 8/19/09 3:17 PM, David Winsemius wrote:
>>>>
>>>>
>>>> On Aug 19, 2009, at 6:11 PM, Noah Silverman wrote:
>>>>
>>>>> Steve,
>>>>>
>>>>> Not sure what to do with this.
>>>>>
>>>>> I have a data.frame.  Don't know how to convert it to a list.
>>>>
>>>> A data.frame is a list.
>>>>
>>>>>
>>>>> Does anybody else have any input on this?
>>>>>
>>>>>
>>>>>
>>>>> On 8/19/09 12:17 PM, Steve Lianoglou wrote:
>>>>>>> Steve,
>>>>>>>
>>>>>>> That makes sense, except that x is a data.frame with about 70
>>>>>>> columns.  So I don't see how it would convert to a list.
>>>>>>
>>>>>> Yeah ... not sure if that's what happening (R class
>>>>>> relationships/testing is still a bit of a mystery to me), but see:
>>>>>>
>>>>>> R> df <- data.frame(a=1:10,b=1:10)
>>>>>> R> is(df)
>>>>>> [1] "data.frame" "list"       "oldClass"   "mpinput"    "vector"
>>>>>>
>>>>>> But
>>>>>>
>>>>>> R> is(df, 'list')
>>>>>> [1] FALSE
>>>>>>
>>>>>> So, in short, I don't know if that's what's happening ... did it fix
>>>>>> your problem, tho?
>>>>>>
>>>>>> -steve
>>>>
>>>> David Winsemius, MD
>>>> Heritage Laboratories
>>>> West Hartford, CT
>>>>
>>
>> David Winsemius, MD
>> Heritage Laboratories
>> West Hartford, CT
>>
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