Steve,

That makes sense, except that x is a data.frame with about 70 columns.  
So I don't see how it would convert to a list.

-N

On 8/19/09 12:09 PM, Steve Lianoglou wrote:
> Howdy,
>
> On Aug 19, 2009, at 2:54 PM, Noah Silverman wrote:
>
>> Hi Steve,
>>
>> No custom kernel. (This is the exact same data that I call svm with.  
>> svm works without a complaint.)
>>
>> traindata is just a dataframe of numerical attributes
>> trainlabels is just a vector of labels. ("good", "bad")
>>
>> Then I call
>>
>> model <- rvm(x,y)
>
> is x really a data.frame? Can you try to turn it into a matrix to see 
> if it will get you over this speed bump?
>
> model <- rvm(as.matrix(x), y)
>
> I reckon if x is a data.frame, R is invoking the rvm function that's 
> meant to work on list(s), rather than the matrix which you think 
> you're passing in.
>
> Does that do the trick?
>
> -steve
>
> -- 
> Steve Lianoglou
> Graduate Student: Computational Systems Biology
>  |  Memorial Sloan-Kettering Cancer Center
>  |  Weill Medical College of Cornell University
> Contact Info: http://cbio.mskcc.org/~lianos/contact
>
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