Dear Kathryrn,
Here is one way:

unique(do.call(rbind,z))

See ?unique, ?do.call and ?rbind for more information.

HTH,

Jorge


On Tue, Jul 28, 2009 at 6:21 PM, kathie <> wrote:

>
> Dear R users...
>
>
> I have a list, "z", below.
>
>
> z<-list(matrix(c(11,11,9,0,0,0),3,2),matrix(c(10,10,10,1,1,1),3,2),
>        matrix(c(7,10,1,1),2,2))
>
> > z
> [[1]]
>     [,1] [,2]
> [1,]   11    0
> [2,]   11    0
> [3,]    9    0
>
> [[2]]
>     [,1] [,2]
> [1,]   10    1
> [2,]   10    1
> [3,]   10    1
>
> [[3]]
>     [,1] [,2]
> [1,]    7    1
> [2,]   10    1
>
>
> >From the list, I need to remove duplicated rows based on the 1st column in
> each "z" element, and then eventually make one matrix as followings;
>
>     [,1] [,2]
> [1,]   11    0      <---- from z[1]
> [2,]    9    0       <---- from z[1]
> [3,]   10    1      <---- from z[2]
> [4,]    7    1      <---- from z[3]
> [5,]   10    1      <---- from z[3]
>
> Any comments will be greatly appreciated.
>
> Regards,
>
> Kathyrn Lord
>
>
>
> --
> View this message in context:
> http://www.nabble.com/make-one-matirx-in-list-after-removing-duplicated-rows-tp24708937p24708937.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide
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>

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