Right on target! Very appreciated. Thanks.

Cheers,
AS

On Fri, Jul 17, 2009 at 4:39 PM, Henrique Dallazuanna <wwwhsd@gmail.com>wrote:

> do.call(rbind, tmp)
>
> On Fri, Jul 17, 2009 at 10:55 AM, Angel Spassov <anspassov@googlemail.com>wrote:
>
>> Dear useRs and developeRs,
>>
>> I am struggling with a simple but not obviously solvable issue. Suppose I
>> have the following list of data.frames called 'tmp':
>>
>> a <- data.frame(a=rnorm(10),b=letters[1:10])
>> (tmp <- list(a,a[1:4,],a[1:7,]))
>>
>> It is known that all data.frames in this list have the same number of
>> columns (and this is a good thing). I want to build a bigger data.frame
>> consisting of all list-members, e.g. the result should look like:
>>
>> (res <- rbind(tmp[[1]],tmp[[2]],tmp[[3]]))
>>
>> The question is how could I do this most efficiently? My real list consist
>> of about 700 data.frames, each with with exactly 10 columns and plenty of
>> rows. The obvious for-loop solution is rather time consuming and therefore
>> I'm looking for something more efficient.
>>
>> Thank you in advance,
>> AS.
>>
>> ps: 'sapply' should somehow do the trick, doesn't it?
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>

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