Dear njhuang86,
Here is one way:

x <- c('a', 't', 'c', 'y', 'g')
y <- c('a', 'a', 'g', 's')
table(factor(y, levels = x))
# a t c y g
# 2 0 0 0 1

HTH,

Jorge


On Tue, Jul 7, 2009 at 3:28 PM, njhuang86 <njhuang86@yahoo.com> wrote:

>
> Hi all,
> Suppose I have x = c('a', 't', 'c', 'y', 'g')
> and also y = c('a', 'a', 'g', 's')
>
> If I do something like x%in%y, I obtain a vector like this: [TRUE, FALSE,
> FALSE, FALSE, TRUE] which I can easily turn into this: [1, 0, 0, 0, 1].
> I was wondering is there anyway for me to get a vector back in return in
> the
> form of: [2, 0, 0, 0, 1]? Essentially, the 2 will tell me that in the first
> position of vector 'x', there were two matches found with vector y.
>
> Thanks a ton in advance!
> --
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