Thanks, that works great.
Andrew

On Fri, May 22, 2009 at 5:42 PM, William Dunlap <wdunlap@tibco.com> wrote:

> > -----Original Message-----
> > From: r-help-bounces@r-project.org
> > [mailto:r-help-bounces@r-project.org] On Behalf Of Andrew Yee
> > Sent: Friday, May 22, 2009 2:16 PM
> > To: r-help@stat.math.ethz.ch
> > Subject: [R] stripchart and ordering of plot
> >
> > Take for example the following stripchart that's created:
> >
> > b <- 1:5
> > a <- 11:15
> > e <- 21:25
> > f <- -11:-15
> >
> > foo <- rbind(b,a,e,f)
> >
> > stripchart(foo ~ rownames(foo))
> >
> > In this case, I would like the bottom part of the plot to be
> > the f vector,
> > followed by the e vector, etc.
> >
> > However, R reorders the matrix and plots according to the
> > alphabetical order
> > of the rownames of foo.  Is there a way to plot the matrix in
> > the current
> > order of the rownames?
>
> If you supply a factor it will use the order of the factor
> levels.  If you supply a character vector, it converts it
> into a factor and the converter puts the levels in alphabetical
> order by default.  Hence one solution is to change that
> character vector into  a factor with the desired order
> of levels:
>   stripchart(foo ~ factor(rownames(foo), levels=c("f","e","a","b"))
>
> Bill Dunlap
> TIBCO Software Inc - Spotfire Division
> wdunlap tibco.com
>
> >
> > Thanks,
> > Andrew
> >
> >       [[alternative HTML version deleted]]
> >
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> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>

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