Well, sum of 1/m! is e--does that answer your question?
Generally, I guess you have to decide how much error you're comfortable
with; then using an error approximation formula, you can back out the M at
which you can stop the sum.  Then you can write a for loop that ends at M.

Hope that helps.


On Wed, Mar 25, 2009 at 8:43 PM, Roslina Zakaria <zroslina@yahoo.com> wrote:

>
> Hi r-users,
>
> How do we evaluate the summation of (1/m!) from 0 to infinity (for
> example).
>
> Any help is very much appreciated.
>
> Thank you.
>
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