Thanks Gabor. Using the data.matrix() approach as outlined in the FAQ works  
for me.

Cheers
Rory

On Mar 3, 2009 4:00pm, Gabor Grothendieck <ggrothendieck@gmail.com> wrote:
> On Tue, Mar 3, 2009 at 10:37 AM, rory.winston@gmail.com> wrote:

> > Hi guys

> >

> > I have a reasonably basic question with zoo usage, but I havent been  
> able

> > to find a satisfactory workaround yet.

> >

> > Heres a simple example of what I'm talking about (the following data  
> frame

> > contains numeric columns that contains NAs):

> >

> >> head(ebs)

> > time src tstamp code bid ask

> > 1 2009-03-03 13:03:29.536 perf.Tib_listener 14980321164

> > EBS.REC.EURJPY=EBS.NaE 123.48 NA

> > 2 2009-03-03 13:03:29.786 perf.FilteringPublisher 14980565658  
> EUR.JPY.SPOT

> > 123.48 123.51

> > 3 2009-03-03 13:03:29.786 perf.Tib_listener 14980566116

> > EBS.REC.EURJPY=EBS.NaE NA 123.51

> > 4 2009-03-03 13:03:30.036 perf.FilteringPublisher 14980824852  
> EUR.JPY.SPOT

> > 123.49 123.50

> > 5 2009-03-03 13:03:30.051 perf.Tib_listener 14980835694

> > EBS.REC.EURJPY=EBS.NaE 123.49 123.50

> > 6 2009-03-03 13:03:30.520 perf.FilteringPublisher 14981302082  
> EUR.JPY.SPOT

> > 123.49 123.51

> >

> >> class(ebs)

> > [1] "data.frame"

> >

> >> class(ebs$bid)

> > [1] "numeric"

> >

> >> any(is.na(ebs$bid))

> > [1] TRUE

> >

> >> class(ebs$ask)

> > [1] "numeric"

> >

> >> foo


> The first argument to zoo cannot be a data frame. From ?zoo



> Usage:



> zoo(x = NULL, order.by = index(x), frequency = NULL)



> Arguments:



> x: a numeric vector, matrix or a factor.



> Also see Question #4 in the zoo faq. From within R:



> library(zoo)

> vignette("zoo-faq")


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