Dear Gundala,
Try this:

> ex<-paste("V",3:9,sep="")
> new.dat<-dat[,ex]
> new.dat

HTH,

Jorge



On Sun, Jan 4, 2009 at 9:36 PM, Gundala Viswanath <gundalav@gmail.com>wrote:

> Dear all,
>
> I have the following data frame:
>
> > dat
>   V1                                 V2   V3 V4    V5   V6   V7   V8   V9
> 1   1 AAAACACCCACCCCCCCCCCCCCCCCCCCCCCCC  9.0 18 12.00 18.0 15.0 12.0  6.0
> 2   1 ACGATACGGCGACCACCGAGATCTACACTCTTCC 18.0  8 12.00 18.0 15.0 12.0 18.0
> 3   1 ACTACTGCTCCCCCCCCACTCCCCCCCCCCCCCC 15.0  8 12.00 12.0 18.0 12.0 12.0
> 4   1 ACTTATACGGCGACCACCGAGATCTACACTCTTT 15.0  6 18.00  6.0 18.0 15.0  9.0
> 5   1 CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC 21.0 21 21.00 21.0 21.0 21.0 21.0
> 6   1 CTACACTCTTTCCCTACACGCCGCTCTTCCGATC 21.0 21 21.00 21.0 21.0 21.0 21.0
> 7   1 TACACCGCCCCCCCCCATCTCCACACTCTCCCCC 12.0 21 12.00 21.0 21.0 21.0 21.0
> 8   1 TGATACGCCTACCACCGCCCTCTACACTCTCTCC 15.0  9 18.00 18.0 15.0 15.0  6.0
> 9   1 TGATACGGCGACCACCGAGATCTACACTCTCTCC 21.0 21 21.00 21.0 21.0 21.0 21.0
> 10  4 TGATACGGCGACCACCGAGATCTACACTCTTTCC 19.5 18 15.75 19.5 16.5 19.5 18.0
> 11  1 TGATACGGCGACCACCGAGGATCTACACTCTTTC 21.0 21 21.00 21.0 21.0 21.0 21.0
> 12  1 TGATACGGCGACCACCGAGGATCTCCACTCTCTC 21.0 21 21.00 21.0 21.0 21.0 21.0
> 13  2 TGCTCCGGCGACCACCGAGATCTACACTCTTTCC 18.0  8 12.00 18.0 13.5 18.0 13.5
> 14  1 TTATACGTCGACCACCGAGATCTACACTCTCTCC 18.0 18 18.00 18.0 18.0 18.0 15.0
> 15  1 TTCTCCGGCGACCACCGAGATCTACACTCTTTCC 18.0  7  9.00 18.0 12.0 18.0 15.0
> 16  1 TTCTCCGGCGACCACCGCGATCTACACTCTTTCC 18.0  7  9.00 18.0 12.0 18.0 15.0
>
>
> My question is how can I extract the column V3 up to V9 into another
> new data frame.
>
> I tried this but failed:
> str <- paste("V", 3:9, sep="")
> print(dat$str)
>
>
>
>
> - Gundala Viswanath
> Jakarta - Indonesia
>
> ______________________________________________
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> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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