Dear John,
Go to https://stat.ethz.ch/mailman/listinfo/r-help  At the bottom, type your
email and then do click on "Unsubscribe or edit options".

HTH,

Jorge



On Sun, Oct 26, 2008 at 11:42 PM, Fresen, John <fresenj@missouri.edu> wrote:

> I signed onto this R-help server.  It's wonderful but I'm getting tooooo
> many e-mails all mixed up with other important e-mails.  I can't cope
> with it all.
> How do I sign off?
>
> Thanks
>
> John
>
> John L. Fresen, PhD
> Department of Statistics, 134N Middlebush Hall
> University of Missouri-Columbia, 65211, MO, US
> (573) 882-9660 (phone)   (573) 884-5524 (fax)
> www.stat.missouri.edu
> -----Original Message-----
> From: r-help-bounces@r-project.org [mailto:r-help-bounces@r-project.org]
> On Behalf Of Martin Ballaschk
> Sent: Saturday, October 25, 2008 7:52 PM
> To: r-help@r-project.org
> Subject: Re: [R] help: selection of data
>
> Hi Jim.
>
> jim holtman schrieb:
> > If you only want the first sequence,
>
> Yes, that's true, I forgot to say that!
>
> >> x <- c(-10, -5, 0, 5, 10, 15, 20)
> >> y <- c(10, 10, 10, -5, -6, -7, 10)
> >> data <- as.matrix( cbind(x, y) )
> >> # if you only want the first 'run', then use 'rle' to find it
> >> mask <- data[,1] > 0 & data[,2] > min(data[,2])
> >> run <- rle(mask)
> >> # now either the first or second will be TRUE, so find it
> >> offset <- cumsum(c(1, run$lengths))  # off set of the start of
> sequence
> >> index <- if (run$values[1]) 1 else 2
> >> new_data <- data[seq(from=offset[index], length=run$lengths[index]),]
> >>
>
> Although I'm far from understanding that -- it seems to work very well
> for
> me. Will have a look into it tomorrow ...
>
> Thanks!
>
> Cheers
> Martin
>
> ______________________________________________
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> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>

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