Dear Alex,
Is this what you want?

# Data set
my=read.table(textConnection("
X8 X9 X10 X102 X110 X177 X283 X284 X286 X292 X297 X306 X308 X314
0  1   0    0    0    1    0    0    0    0    0    0    0    0
0  0   0    0    1    0    0    0    0    0    0    0    1    0
0  1   0    0    0    0    0    0    0    0    0    0    1    0
1  0   0    0    1    0    0    0    0    1    0    0    0
 0"),header=TRUE)
closeAllConnections()
rownames(my)=paste('s',1:4,sep="")

# Samples
res=list()
for(i in 1:5) res[[i]]<- my[,sample(colnames(my),5)]
res

HTH,

Jorge


On Wed, Oct 15, 2008 at 10:07 AM, Alex99 <loyola9988@yahoo.com> wrote:

>
> Hi everyone,
>
> I have a dataset(named "Mydata") which includes 4 different variables
> named;
> s1,s2,s3,s4 .Each variable(symptom) has 14 patients.
> I need to use random sampling to make, 5 different samples from my data
> with
> 5 patients in each sample. i.e. using all 4 variables I need to make 5
> different samples by changing patients(with 5 patients in each sample).
>
>
>   X8 X9 X10 X102 X110 X177 X283 X284 X286 X292 X297 X306 X308 X314
> s1  0  1   0    0    0    1    0    0    0    0    0    0    0    0
> s2  0  0   0    0    1    0    0    0    0    0    0    0    1    0
> s3  0  1   0    0    0    0    0    0    0    0    0    0    1    0
> s4  1  0   0    0    1    0    0    0    0    1    0    0    0    0
>
>
> I used this code:
>
> temp=list(NULL)
> for(i in 1:5) {temp[i]<-sample(Mydata,5, replace=F)} show(temp)
>
> but I get the following error:
> "number of items to replace is not a multiple of replacement length"
>
> any idea why I get this eeror message and how can I fix it?
> Thanks a lot.
>
> --
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> Sent from the R help mailing list archive at Nabble.com.
>
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