Try this:


lines <- "77.56787,22.09909,0 73.26787,21.09909,0
76.53487,23.09909,0 75.56787,22.09909,0
76.54587,22.09909,0 76.56787,22.03509,0
75.56457,22.05609,0 76.56787,22.05609,0"

ln <- readLines(textConnection(lines))

t(sapply(strsplit(ln, "(,)|(,0+)"), as.numeric))

On Fri, Sep 12, 2008 at 9:08 AM, Ajay ohri <ohri2007@gmail.com> wrote:

>   Hi All,
>
> I have the following data in one column for each row , (each value is
> like x1,y1,z1 space x2,y2,z2 space....)
>
> 77.56787,22.09909,0 73.26787,21.09909,0
> 76.53487,23.09909,0 75.56787,22.09909,0
> 76.54587,22.09909,0 76.56787,22.03509,0
> 75.56457,22.05609,0 76.56787,22.05609,0
>
> Note all z values are O (hence ,0 can be treated as a delimiter)
>
> How do I split this column into multiple columns for each row.
>
> Regards,
> Ajay
>
> www.decisionstats.com
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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