Try this:

str <- " 1975 01 7711.16"

# Find the position of the space in string
gregexpr("[[:space:]]", str)

# Remove the space
gsub("[[:space:]]", "", str)


On Wed, Sep 10, 2008 at 9:07 AM, Megh Dal <megh700004@yahoo.com> wrote:

> I have following
>
> " 1975 01 7711.16"
>
> Here I need to identify where the <space> is there and then concatenate
> rest of the digits without <space>, i.e. I want to have "1975017711.16". Is
> there any R function?
>
> Regards,
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

	[[alternative HTML version deleted]]

