Use this:

plot(January[c(3, 6)])

On Fri, Sep 5, 2008 at 8:52 AM, Steve Murray <smurray444@hotmail.com> wrote:

>
> Sorry! Hopefully just one more question!
>
> I'm now trying to plot columns 3 and 6. I've tried:
>
> > plot(January[3:6])
>
> ...but this plots columns 4 and 5 too!
>
>
> I've also tried:
>
> > plot(January[3],January[6])
> > plot(January[3,6])
> > plot(January[3]:January[6])
>
> But these don't produce the right results (instead, errors!)
>
> Again, I'm sure it's a just a small (but important) detail that I'm
> missing, and I'd be very grateful if anyone could help me out.
>
> Many thanks again,
>
> Steve
>
> ________________________________
> Date: Thu, 4 Sep 2008 13:52:03 -0300
> From: wwwhsd@gmail.com
> To: smurray444@hotmail.com
> Subject: Re: [R] Plotting using 'if' statements
> CC: r-help@r-project.org
>
> Use '&':
>
> plot(January[January[,3]> 0 & January[,3] < 2, 3:4])
>
> On Thu, Sep 4, 2008 at 1:47 PM, Steve Murray  wrote:
>
>
>
> Ah that's great, thank you very much.
>
>
>
> As a follow-on, in the same format, how would I plot where column 3 is
> greater than 0 *but also less than 2*?
>
>
>
> Once again, any help is much appreciated.
>
>
>
>
>
> Thanks,
>
>
>
> Steve
>
>
>
> ________________________________
>
> Date: Thu, 4 Sep 2008 13:39:12 -0300
>
> From: wwwhsd@gmail.com
>
> To: smurray444@hotmail.com
>
> Subject: Re: [R] Plotting using 'if' statements
>
> CC: r-help@r-project.org
>
>
>
> Try this:
>
>
>
> plot(January[January[,3]> 0, 3:4])
>
>
>
> On Thu, Sep 4, 2008 at 1:28 PM, Steve Murray  wrote:
>
>
>
>
>
>
>
>
>
>
>
> Dear all,
>
>
>
>
>
>
>
> I have a dataset of four columns, and I wish to plot (as a scatter graph)
> the values of the third column where the values are greater than zero, and
> the fourth column.
>
>
>
>
>
>
>
> I tried doing this via the plot command itself, but got into a bit of a
> mess (resulting in errors!). My dataframe is called 'January':
>
>
>
>
>
>
>
> > plot(January[3(>0):4])
>
>
>
> Error: unexpected '>' in "plot(January[3(>"
>
>
>
>
>
>
>
>
>
>
>
> After a few variations on this, I thought I'd try making a new object which
> includes all values from the third column of January>0 (to plot in a
> separate step) as follows:
>
>
>
>
>
>
>
> > JanFilter <- January[3]>0
>
>
>
>
>
>
>
> No error here. However, when I display the 'values' of JanFilter, it shows
> that instead of keeping the numerical values, the above operation simply
> displays the results of the logical test:
>
>
>
>
>
>
>
> > head(JanFilter)
>
>
>
>                           Value
>
>
>
> [1,]                       FALSE
>
>
>
> [2,]                        TRUE
>
>
>
> [3,]                        TRUE
>
>
>
> [4,]                        TRUE
>
>
>
> [5,]                        TRUE
>
>
>
> [6,]                        TRUE
>
>
>
>
>
>
>
>
>
>
>
> This is obviously no good for plotting the numerical values on axes!
>
>
>
>
>
>
>
> So my question is, how do I perform 'if' statements in order to filter out
> various parts of a dataset, for plotting on a graph.
>
>
>
>
>
>
>
> Many thanks,
>
>
>
>
>
>
>
> Steve
>
>
>
>
>
>
>
> ______________________________________________
>
>
>
> R-help@r-project.org mailing list
>
>
>
> https://stat.ethz.ch/mailman/listinfo/r-help
>
>
>
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
>
>
>
> and provide commented, minimal, self-contained, reproducible code.
>
>
>
>
>
>
>
>
>
> --
>
> Henrique Dallazuanna
>
> Curitiba-Paraná-Brasil
>
> 25° 25' 40" S 49° 16' 22" O
>
>
>
>
>
>
>
> _________________________________________________________________
>
> Make a mini you and download it into Windows Live Messenger
>
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>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
>
> 25° 25' 40" S 49° 16' 22" O
>
>
>
> _________________________________________________________________
> Win New York holidays with Kellogg's & Live Search
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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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