lt[!is.na(lt)] is a rather obvious way...


On Fri, Aug 22, 2008 at 9:41 PM, Dong-hyun Oh <oh.dongh@gmail.com> wrote:

> Dear useRs,
>
> I would like to know the way of deleting NA in list().
>
> Following is a example.
>
> lt <- list(a = 1:3, b = NA, c = letters[1:3], d = NA)
>
> for(i in length(lt):1) {
>        if(is.na(lt[[i]])) lt[[i]] <- NULL
> }
>
> How to simplify for() loop by using (l)apply family?
>
> Thank you in advance.
>
>
>
>
> =========================================================
> Dong-hyun Oh
> Center of Excellence for Science and Innovation Studies
> Royal Institute or Technology, Sweden
> e-mail: oh.dongh@gmail.com
> cel: +46 73 563 45 22
>
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