I am looking for the most efficient way to replace all occurrences of NaN in a data frame with NA.  I can do this with a double loop, but it seems that there should be a higher level and more efficient way.  With is.na, I could use ifelse, but if.nan seems not to have similar capabilities.

 

TIA,

Jon Peck

 

Jon K. Peck

jkpeck@aya.yale.edu

 


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