Dear Gundala,

Try this:

x=as.matrix(read.table(textConnection("
4.482909e-01 0.55170907
9.479594e-01 0.05204063
8.923553e-01 0.10764474
9.295003e-01 0.07049966
8.880434e-01 0.11195664
9.197367e-01 0.08026327
9.431232e-01 0.05687676
9.460356e-01 0.05396442
6.053829e-01 0.39461708
9.515173e-01 0.04848268"),header=FALSE,sep=""))

index=apply(x,1,function(x) ifelse(x[1]>x[2],'Group1','Group2'))
index
 [1] "Group2" "Group1" "Group1" "Group1" "Group1" "Group1" "Group1" "Group1"
"Group1" "Group1"


HTH,

Jorge



On Thu, Jul 31, 2008 at 11:00 PM, Gundala Viswanath <gundalav@gmail.com>wrote:

> Hi,
>
> I have the following (M x N) matrix, where M = 10 and N =2
> What I intend to do is to group index of (M) based on this condition
> of "x_mn" , namely
>
> For each M,
> If x_m1 > x_m2, assign index of M to Group1
> otherwise assign index of M into Group 2
>
>
> > x
>               [,1]       [,2]
>  [1,] 4.482909e-01 0.55170907
>  [2,] 9.479594e-01 0.05204063
>  [3,] 8.923553e-01 0.10764474
>  [4,] 9.295003e-01 0.07049966
>  [5,] 8.880434e-01 0.11195664
>  [6,] 9.197367e-01 0.08026327
>  [7,] 9.431232e-01 0.05687676
>  [8,] 9.460356e-01 0.05396442
>  [9,] 6.053829e-01 0.39461708
>  [10,] 9.515173e-01 0.04848268
>
> Is there a simple way to do it in R?
> - Gundala Viswanath
> Jakarta - Indonesia
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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