Sorry, my mistake, - it works both ways with a correct example and neither
way with the wrong example.

k


On Thu, Jun 26, 2008 at 4:25 PM, Wacek Kusnierczyk <
Waclaw.Marcin.Kusnierczyk@idi.ntnu.no> wrote:

> >>>     sapply(dats,function(x){sapply(x,min)})
> >>>
> >> you can achieve the same with
> >>
> >> sapply(dats, sapply, min)
> >>
> >>
> >>
> > Did you actually try it?
> >
> >
> >> dats <- data.frame(1:10,2:11)
> >> sapply(dats,sapply,min)
> >>
> >       X1.10 X2.11
> >  [1,]     1     2
> >  [2,]     2     3
> >  [3,]     3     4
> >  [4,]     4     5
> >  [5,]     5     6
> >  [6,]     6     7
> >  [7,]     7     8
> >  [8,]     8     9
> >  [9,]     9    10
> > [10,]    10    11
> >
> > Sapply doesn't (or can't?) pass arguments to another sapply -- maybe  the
> > trick can be done without an anonymous function but not the way you
> > suggested.
> >
> >
>
> did you actually read the original mail?  there dats was a *list* of
> data frames.
> try this:
>
> d = data.frame(a=1:10. b=11:20)
> l = list(a=d, b=d)
> sapply(l, sapply, min)
> sapply(l. function(d) sapply(d, min))
>
> did you actually read the docs for sapply?  there ... stands for
> optional arguments to FUN.
> try this:
>
> ?sapply
>
>
> vQ
>
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