Try this:

which(apply(t(m) == target, 2, all))

On Wed, Jun 11, 2008 at 8:58 AM, Esmail Bonakdarian <esmail.js@gmail.com>
wrote:

> Hi,
>
> I have matrix of bits and a target vector. Is there an
> efficient way to search the rows of the matrix for the target?
> I am interested in the first row index where target is found.
>
> Example:
>
> > source("lookup.R")
>      [,1] [,2] [,3] [,4] [,5]
>  [1,]    1    0    1    1    0
>  [2,]    1    1    0    1    0
>  [3,]    0    0    1    0    0
>  [4,]    1    0    0    1    1
>  [5,]    1    0    1    1    1
>  [6,]    1    1    0    0    1
>  [7,]    1    0    0    1    1
>  [8,]    0    0    1    1    1
>  [9,]    0    1    1    0    1
> [10,]    0    0    0    1    0
>
> target:  1 1 0 1 1
>
> Should return -1 (or some other indicator) since the
> target was not found in any of the rows.
>
>
>
> > source("lookup.R")
>      [,1] [,2] [,3] [,4] [,5]
>  [1,]    0    0    1    1    0
>  [2,]    1    0    0    0    0
>  [3,]    1    0    0    0    0
>  [4,]    1    1    0    0    0
>  [5,]    1    1    1    0    0
>  [6,]    0    0    1    1    0
>  [7,]    0    1    1    1    0
>  [8,]    0    0    1    1    0
>  [9,]    1    1    0    1    1
> [10,]    1    0    1    0    0
>
> target:  1 1 0 1 1
>
> Should return 9 since the target was  found in row 9
>
>
> If the target is found, it is no longer necessary to keep
> searching the rest of the matrix (which may be quite large)
>
> The data/size etc may change of course, but target will
> always have the same number of "columns" as the matrix.
>
> I tried variations of "which", and a for loop
> comparing pop[i,] to target without much success, nor
> did google yield any results. I am hoping someone here
> can provide a suggestion.
>
> Thanks,
>
> EB
>
>
> ---------------------------------------------
>
> # Here is the code that generates the above data
>
> create_bin_string <- function(len)
> {
>  sample(0:1, len, replace=T)
> }
>
> ROWS = 10
> COLS =  5
> pop = matrix(create_bin_string(ROWS*COLS), ROWS, COLS, byrow=T)
>
>
>
> target=c(1, 1, 0, 1, 1)
>
> # my population
> print(pop)
>
> # I am looking for the index of this in pop
> # if present (else -1?)
> cat("\ntarget: ", target, "\n")
>
>
>
> ##
> ## this is NOT working
> ## plus it would continue to search
> ## after it found the target
> ##
> for(i in ROWS)
>   if (pop[i,] == target)
>      cat("\nfound in row: ", i, "\n\n")
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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