I had to to get the data as a matrix and fix a couple of other things-  If
you would like for me to post my solution then I can.  I appoligize my
fingers went faster than my brain.

Stephen

On Wed, Jun 11, 2008 at 1:55 PM, Marc Schwartz <marc_schwartz@comcast.net>
wrote:

> on 06/11/2008 12:44 PM stephen sefick wrote:
>
>> #I am having trouble figuring out this one.  I have read the help and I am
>> at a loss.  what am I missing
>>
>> x <- structure(list(X = structure(c(6L, 5L, 9L, 2L, 10L, 8L, 7L, 3L,
>> 13L, 12L, 11L, 4L, 1L, 1L, 1L), .Label = c("", "April", "August",
>> "December", "February", "January", "July", "June", "March", "May",
>> "November", "October", "September"), class = "factor"), X2006 =
>> c(5987.387,
>> 6478.592, 8386, 4651.273, 4339.167, 4631.978, 5217.306, 5846.903,
>> 3867.825, 3886.434, 3959.668, 3848.853, NA, NA, NA), X2007 = c(4354.516,
>> 5924.315, 5559.468, 3967.5, 5053.56, 4808.694, 4017.632, 3969.883,
>> 3910.236, 3782.094, 3961.286, 3711.262, NA, NA, NA), X2008 = c(3685.789,
>> NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA)), .Names = c("X",
>> "X2006", "X2007", "X2008"), class = "data.frame", row.names = c(NA,
>> -15L))
>>
>> barplot(x)
>>
>> #I would like the months to be on the x-axis and then have the bars be the
>> values for the year
>>
>
> Is this what you want?
>
>  barplot(t(x[-1]), names.arg = x$X, las = 2)
>
> Note that the 'height' argument for barplot() needs to be either a vector
> or a matrix.
>
> HTH,
>
> Marc Schwartz
>
>


-- 
Let's not spend our time and resources thinking about things that are so
little or so large that all they really do for us is puff us up and make us
feel like gods. We are mammals, and have not exhausted the annoying little
problems of being mammals.

-K. Mullis

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