Try this:

for(i in 1:100)assign(sprintf("id.%d", i), value = sample(1))
id <- ls(patt = "id.[0-9]")

On Wed, Jun 4, 2008 at 7:52 PM, Manli Yan <manliyanrhelp@gmail.com> wrote:

>  I need to create 100 variable ,whose name is id.1,id.2~~~~id.100
>  then I need to let a vector say id<-c(id.1,id.2....id.100)
>  any easy way to do this?
>  thanks a lot~
>
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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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