Not exactly clear what you are asking for.  Your data.frame.table does not
seem related to the original 'orig'.  What exactly are you expecting as
output?

On Wed, May 21, 2008 at 10:16 PM, maiya <maja.zaloznik@gmail.com> wrote:

>
> i appologise for the trivialness of this post - but i've been searching the
> forum wothout luck - probably simply because it's late and my brain is
> starting to go..
>
> i have a frequency table as a matrix:
>
> orig<-matrix(c(40,5,30,25), c(2,2))
> orig
>     [,1] [,2]
> [1,]   40   30
> [2,]    5   25
>
> i basically need a random sample say 10 from 100:
>
>     [,1] [,2]
> [1,]   5   2
> [2,]    0   3
>
> i got as far as
>
> orig<-as.data.frame.table(orig)
> orig
>  Var1 Var2 Freq
> 1    A    A   10
> 2    B    A    5
> 3    A    B   30
> 4    B    B   25
>
> and then perhaps
>
> individ<-rep(1:4, times=orig$Freq)
>
> which gives a vector of the 100 individuals in each of the 4 groups -
> cells,
> but I'm
> (a) stuck here and
> (b) afraid this is a very round-about way at getting to what I want i.e. I
> can now sample(individ, 10), but then I'll have a heck of a time getting
> the
> result back into the original matrix form....
>
> sorry again, just please tell me the simple solution that I've missed?
>
> thanks!
>
> maja
>
> --
> View this message in context:
> http://www.nabble.com/disaggregate-frequency-table-into-flat-file-tp17396040p17396040.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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