Not sure exactly what you want since you did not provide any data or an
example of the expected out'  Here is my interpretation of what you were
asking:

> x <- sample(1:20)
> x
 [1]  6 16  8  1 17 11  2 19 18  5 15 13  3 20  9 14  7 10 12  4
>
> cumsum(x) / seq_along(x)
 [1]  6.000000 11.000000 10.000000  7.750000  9.600000  9.833333  8.714286
10.000000 10.888889 10.300000
[11] 10.727273 10.916667 10.307692 11.000000 10.866667 11.062500 10.823529
10.777778 10.842105 10.500000
>


On Wed, May 21, 2008 at 9:48 PM, Jacques Wagnor <jacques.wagnor@gmail.com>
wrote:

> Dear List,
>
> Does there exist a function that calculates a cumulative average?
> Neither running() from library(gregmisc) nor running.mean() from
> library(igraph) seems to be able to give a cumulative average.
>
> Any help or pointers would be greatly appreciated.
>
> Jacques
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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