Yea, thanks all. I checked back and I got a few things mistyped.
The array is 650,000 and it took 25 seconds :p. It's acceptable. Just that I
had too many variable at the time I ran it.

Also, seems like sprintf is a little faster.

Thanks all.

Anh Tran


On Mon, May 12, 2008 at 2:55 PM, Uwe Ligges <ligges@statistik.tu-dortmund.de>
wrote:

>
>
> Anh Tran wrote:
>
> > Thanks. formatC(flag) works.
> >
> > But it's awefully slow. I try to do that for 65000 numbers (generating
> > ID
> > for each item) and it seems like forever.
> >
>
> On my not that recent laptop:
>
> > system.time(formatC(1:65000, width=10, flag="0"))
>   user  system elapsed
>   1.92    0.00    1.94
>
>
> I think 2 seconds is less than "forever".
>
> Uwe Ligges
>
>
>
>
>
>
>  Is there any faster way?
> >
> > Thank all.
> >
> > Anh Tran
> >
> > On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges <
> > ligges@statistik.uni-dortmund.de> wrote:
> >
> >
> > > Anh Tran wrote:
> > >
> > >  Hi,
> > > > What's one way to convert an integer to a string with preceding 0's?
> > > > such that
> > > > '13' becomes '00000000013'
> > > > to be put into a string
> > > >
> > > > I've tried formatC, but they removes all the zeros and replace it
> > > > with
> > > > blanks
> > > >
> > > >  Not so for me:
> > >
> > > formatC(13, digits=10, flag="0")
> > >
> > > Uwe LIgges
> > >
> > >
> > >
> > >  Thanks
> > > >
> > > >
> > > >
> >
> >


-- 
Regards,
Anh Tran

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