Try this also:

sapply(list(d1, d2, d3), "[", 1:max(sapply(list(d1, d2, d3), length)))

On Mon, May 5, 2008 at 7:46 PM, T.D.Rudolph <prairie.picker@gmail.com>
wrote:

>
> I have numerous objects, each containing continuous data representing the
> same variable, movement rate, yet each having a different number of rows.
> e.g.
> d1<-as.matrix(rnorm(5))
> d2<-as.matrix(rnorm(3))
> d3<-as.matrix(rnorm(6))
>
> How can I merge these three columns side-by-side in order to create a
> table
> regardless of the difference in length?  I wish to analyze the output in a
> spreadsheet format.
>
> Thanks!
> Tyler
> --
> View this message in context:
> http://www.nabble.com/merge-numerous-columns-of-unequal-length-tp17071464p17071464.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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