Dear Marcelha,

Is this what you want?

x="
Values           1      2     3    4     5
Frequency      10   34   56   67   98
Factor           105   50   60  150  200"

# Data set
m=read.table(textConnection(x),header=FALSE)

# Weights
w=as.numeric(m[m$V1=="Frequency",2:6]/m[m$V1=="Factor",2:6])

# Plot
plot(1:5,as.numeric(w),type='h',xlab='Value',ylab='Frequency/Factor',col=1:5,main='Your
plot')

# The same using barplot
barplot(as.numeric(w),1:5,space=.1,width=.8,col=1:5,xlab='Value',ylab='Frequency/Factor',main='Your
plot')


HTH,

Jorge



On Sun, Apr 27, 2008 at 12:41 PM, marcelha mukim <urianha@gmail.com> wrote:

> Hi Sarah:
>
> Thank you very much, but my problem remains. What I want is not duplicate
> the sample, but be able to divide each frequency for a factor(specific for
> each value).For example:
>
> Values           1      2     3    4     5
> Frequency      10   34   56   67   98
> Factor           105   50   60  150  200
>
> Actually Im plotting: plot(Values, Frequency/Factor, type="b"). But I dont
> know how to visualize the probability distribution. On the hand  to modify
> the "hist" function to include this Factor seems to be a daunting task.
>
> any other advise will be welcome
>
> thank you
>
> m.
>
>
>
> On Sun, Apr 27, 2008 at 9:11 AM, Sarah Hardy <sarah.hardy@maine.edu>
> wrote:
>
> > This is a reply to:
> >
> > Message: 43
> >
> > Date: Sun, 27 Apr 2008 02:41:36 -0400
> >
> > From: "marcelha mukim" <urianha@gmail.com>
> >
> > Subject: [R] how to modify the histogram's frequencies
> >
> > To: r-help@r-project.org
> >
> > Message-ID:
> >
> >      <80f5a0c30804262341x3f04d141g65f4fc2d576672f9@mail.gmail.com>
> >
> > Content-Type: text/plain
> >
> >
> >
> > Hi:
> >
> >
> >
> >
> >
> > I have been trying to figure out a simple way to plot an histogram whose
> >
> > frequencies are modified by a factor (associated with each value).
> >
> >
> >
> >
> >
> > Actually what I did was plotting each value with its modified
> >
> > frequency(using plot($values, $frequency, type="h")), but it doesnt take
> >
> > into account the probability distribution(which is necessary).
> >
> >
> >
> > I think you should be able to:
> >
> >
> >
> > newvalue=rep($value,$frequency)
> >
> > hist(new,value,freq=F)
> >
> >
> >
> > Sarah Hardy
> >
> > sarah.hardy@maine.edu
> >
> >
> >        [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]

