>  p<-function(x){
+  for(i in 1:teste2[k]+1){
+  p2=c+teste2[3+i]*x^(i-1)
+ c=p2}
+ return(c)}
> p3<-p(x)

if i make this i can use a p(x) calling a function in anohter function? no ,
right?

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