Thank you so much to Jim and Mark for their advices. Now I solved the
problem I had using a new approach.

Best,

Jorge


On Mon, Apr 21, 2008 at 12:53 PM, jim holtman <jholtman@gmail.com> wrote:

> Will this do it for you:
>
> # Seed and data frames X, Y and Z
> set.seed(123)
> X=matrix(rnorm(300),ncol=5)
> Y=matrix(rpois(300,10),ncol=5)
> Z=matrix(rexp(300,1),ncol=5)
>
> index <- seq(1, by=3, length=nrow(X))
> FINAL <- matrix(ncol=5, nrow=3*nrow(X))
> FINAL[index,] <- X
> FINAL[index + 1,] <- Y
> FINAL[index + 2,] <- Z
>
>
> On Mon, Apr 21, 2008 at 11:44 AM, Jorge Ivan Velez
> <jorgeivanvelez@gmail.com> wrote:
> > Dear R-users,
> >
> > I've been working with three different data sets (X, Y and Z) with the
> same
> > dimension (i.e, n \times k). What I needed to do was to conform a 4th
> data
> > set, i.e. FINAL, which first row was the X's first row, its second row
> was
> > the Y's first row, and its third row was the Z's first row, and so on.
> >
> > My code is below. Is it possible to avoid the loop?
> >
> > Thanks in advance,
> >
> > Jorge
> >
> >
> >
> > # ----- Code starts here
> >
> > # Seed and data frames X, Y and Z
> > set.seed(123)
> > X=matrix(rnorm(300),ncol=5)
> > Y=matrix(rpois(300,10),ncol=5)
> > Z=matrix(rexp(300,1),ncol=5)
> >
> > # First five columns and rows
> > X[1:3,1:5]
> > Y[1:3,1:5]
> > Z[1:3,1:5]
> >
> > # FINAL' six rows
> > res=NULL; for(i in 1:nrow(X)) res=rbind(res,X[i,],Y[i,],Z[i,])
> > FINAL=data.frame(from.data=c('X','Y','Z'),res)
> > FINAL[1:9,1:6]
> >
> > # ----- Code ends here
> >
> >        [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
>
>
> --
> Jim Holtman
> Cincinnati, OH
> +1 513 646 9390
>
> What is the problem you are trying to solve?
>

	[[alternative HTML version deleted]]

