Dear Bert,

Thanks a lot for help. I tried and got:

> x2[x2[["name"]] %in% y,]
[1] name id
<0 rows> (or 0-length row.names)
>

Any suggestions?

Alex

On Fri, Apr 11, 2008 at 2:49 PM, Bert Gunter <gunter.berton@gene.com> wrote:

> 1. Strictly speaking, y is a one-column matrix if it has a non-null dim
> attribute (it also is a vector).
>
> 2. ?match  or ?"%in%"   tells you what to do.
>
> x2[x2[["name"]] %in% y,]
>
> is what you want.
>
>
>
>
> -----Original Message-----
> From: r-help-bounces@r-project.org [mailto:r-help-bounces@r-project.org]
> On
> Behalf Of ss
> Sent: Friday, April 11, 2008 11:23 AM
> To: r-help@r-project.org
> Subject: [R] How to match some patterns in a matrix
>
> Dear all,
>
> I have a data frame called x2, which looks like:
>
> > dim(x2)
> [1] 2237     2
> > x2[1:4,1:2]
>    name                       id
> 1 STye                      hggd3
> 2 STy2                      bffbd2
> 3 qw22e                    bdbdbbbd7
> 4 deffrdff                    nnshfd3
>
> and a vector called y, which looks like:
>
> > dim(y)
> [1] 135   1
> > y[1:3,1]
> [1] ABCDE BDH5  DESRP1
>
> y is a subset of x2$name and I want to select the rows in x2 whose 'name'
> match
> y. Is there an easy way to do so?
>
> I tried subset(x2, y) but it did not work.
>
> Thanks much for your advice.
>
> Alex
>
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