Hi,

This may be a stupid question, but how are the "std. error" values returned
by lm() calculated? For example

> summary(lm)

Call:
lm(formula = log10(moments[2, 1:10]) ~ log10(L_vals[1:10]))

Residuals:
       Min         1Q     Median         3Q        Max
-0.0052534 -0.0019473  0.0006785  0.0011740  0.0059541

Coefficients:
                     Estimate Std. Error t value Pr(>|t|)
(Intercept)         -0.520639   0.002488  -209.2 3.05e-16 ***
log10(L_vals[1:10])  0.112666   0.003446    32.7 8.35e-10 ***

I can't find any documentation on this.

Regards,

Nicky Chorley

	[[alternative HTML version deleted]]

