
Brilliant! 

> t1=matrix(1:15,5,3)
> t1
     [,1] [,2] [,3]
[1,]    1    6   11
[2,]    2    7   12
[3,]    3    8   13
[4,]    4    9   14
[5,]    5   10   15
> t2=1:5
> t2
[1] 1 2 3 4 5

> sweep(t1, 1, t2)
     [,1] [,2] [,3]
[1,]    0    5   10
[2,]    0    5   10
[3,]    0    5   10
[4,]    0    5   10
[5,]    0    5   10

> Date: Sun, 2 Mar 2008 14:56:22 -0300
> From: wwwhsd@gmail.com
> To: bozhou1981@hotmail.com
> Subject: Re: [R] elegant way to minus on each row of a matrix
> CC: r-help@r-project.org
> 
> Try this:
> 
> sweep(mat, 1, vec)
> 
> 
> On 02/03/2008, Bo Zhou <bozhou1981@hotmail.com> wrote:
> >
> > How to do this in an elegant way formatrix/data frame/zoo?
> >
> > mat=
> > 1 2 3
> > 4 5 6
> > 7 8 9
> >
> > vector=
> > 1
> > 2
> > 3
> >
> >
> > result=
> > 0 1 2
> > 2 3 4
> > 4 5 6
> >
> > ie
> > 1-1  2-1  3-1
> > 4-2  5-2  6-2
> > 7-3  8-3  9-3
> >
> > Thanks in advance.
> >
> > _________________________________________________________________
> >
> >
> > 08
> > 	[[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
> 
> 
> -- 
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O

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