
Hi Dimitris and everyone

I tried this but now I know why it didn't work out for me initially.

> t1=matrix(1:10,5,2)
> t2=matrix(1,5,1)
> t2
     [,1]
[1,]    1
[2,]    1
[3,]    1
[4,]    1
[5,]    1
> t1
     [,1] [,2]
[1,]    1    6
[2,]    2    7
[3,]    3    8
[4,]    4    9
[5,]    5   10
> t1-as.vector(t2)
     [,1] [,2]
[1,]    0    5
[2,]    1    6
[3,]    2    7
[4,]    3    8
[5,]    4    9
> t1-t2
Error in t1 - t2 : non-conformable arrays

I'm too used to Matlab I guess.

Cheers,

Bo


> Date: Sun, 2 Mar 2008 18:56:15 +0100
> From: Dimitris.Rizopoulos@med.kuleuven.be
> To: bozhou1981@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] elegant way to minus on each row of a matrix
> 
> try this:
> 
> mat <- matrix(1:9, 3, 3, TRUE)
> dat <- as.data.frame(mat)
> vec <- 1:3
> 
> result.mat <- mat - vec
> result.dat <- dat - vec
> result.mat
> result.dat
> 
> 
> I hope it helps.
> 
> Best,
> Dimitris
> 
> ----
> Dimitris Rizopoulos
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
> 
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
> Web: http://med.kuleuven.be/biostat/
>       http://www.student.kuleuven.be/~m0390867/dimitris.htm
> 
> 
> Quoting Bo Zhou <bozhou1981@hotmail.com>:
> 
> >
> > How to do this in an elegant way formatrix/data frame/zoo?
> >
> > mat=
> > 1 2 3
> > 4 5 6
> > 7 8 9
> >
> > vector=
> > 1
> > 2
> > 3
> >
> >
> > result=
> > 0 1 2
> > 2 3 4
> > 4 5 6
> >
> > ie
> > 1-1  2-1  3-1
> > 4-2  5-2  6-2
> > 7-3  8-3  9-3
> >
> > Thanks in advance.
> >
> > _________________________________________________________________
> >
> >
> > 08
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> >
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> >
> >
> 
> 
> 
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