try this:

> x <- " ID    val
+ 1  A  0.100
+ 2  B  0.001
+ 3  C -0.100
+ 4  A  0.200
+ "
> x <- read.table(textConnection(x), header=TRUE)
> (z <- tapply(x$val, x$ID, sum))
     A      B      C
 0.300  0.001 -0.100
> data.frame(ID=names(z), val=z)
  ID    val
A  A  0.300
B  B  0.001
C  C -0.100
>



On 5/29/07, Young Cho <young.stat@gmail.com> wrote:
>
> I have data.frame's with IDs and multiple columns. B/c some of IDs showed
> up
> more than once, I need sum up colum values to creat a new dataframe with
> unique ids.
>
> I hope there are some cheaper ways of doing it...  Because the dataframe
> is
> huge, it takes almost an hour to do the task.  Thanks so much in advance!
>
> Young
>
> # -------------------------  examples are here and sum.dup.r is at the
> bottom.
>
> > x = data.frame(ID = c('A','B','C','A'), val=c(0.1,0.001,-0.1,0.2))
> > x
> ID    val
> 1  A  0.100
> 2  B  0.001
> 3  C -0.100
> 4  A  0.200
> > sum.dup(x)
> ID    val
> 1  A  0.300
> 2  B  0.001
> 3  C -0.100
>
>
>
> sum.dup <- function( x ){
>
>        d.row = which(duplicated(x$ID))
>        if( length(d.row) > 0){
>                id = x$ID[d.row]
>                com.val = x[-d.row,]
>                for(i in 1:length(id)){
>                        s = sum(x$val[ x$ID == id[i] ])
>                        com.val$val[ com.val$ID == id[i] ] = s
>                }
>                ix = sort(as.character(com.val[,1]),index.return=T)
>                return(com.val[ix$ix,])
>        }else{
>                ix = sort(as.character(x[,1]),index.return=T)
>                return(x[ix$ix,])
>        }
>
> }
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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