l used the following code to generate a sample and then calculated then  did a log rank test.can l get the normal version of the logrank eg sqrt  of the chisqr(1) will give you the N~(0,1).
  from my sample can i use the above expression to get the normal dist from the result of the log rank test.
  thank
  
      s=1
       while(s!=0){ n=100
         m<-matrix(nrow=n,ncol=4)
         colnames(m)=c("treatmentgrp","strata","censoringTime","survivalTime")                  
        for(i in 1:n)  m[i,]<-c(sample(c(1,2),1,replace=TRUE),sample(c(1,2),1,replace=TRUE),rexp(1,0.07),rexp(1,0.02))                                                                    
      m<-cbind(m,0)
        m[m[,3]>m[,4],5]<-1
         colnames(m)[5]<-"censoring"
      
act.surv.time<-pmin(m[,"censoringTime"],m[,"survivalTime"])
  
m<-cbind(m,act.surv.time)
      print(m)
      write.table(m,”clipboard”,sep=”\t”,col.names=NA)
      print(“.................”)
      print(“the logrank test”)
      b=data.frame(m)
      c=  survdiff(Surv(act.surv.time,censoring)~treatmentgrp,data=b)
      print(c)
      s=s-1
      print(“...............................................................”)
      }
    

       
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