> x <- "   x
+ 1 2
+ 2 4
+ 3 1
+ 4 3
+ 5 3
+ 6 2
+ "
> x <- read.table(textConnection(x), header=TRUE)
> data.frame(sum=tapply(x$x, rep(1:(nrow(x) / 2), each=2), sum))
  sum
1   6
2   4
3   5


On 7/14/06, Sachin J <sachinj.2006@yahoo.com> wrote:
>
> Hi,
>
> How can I achieve this in R. Dataset is as follows:
>
> >df
>    x
> 1 2
> 2 4
> 3 1
> 4 3
> 5 3
> 6 2
>
> structure(list(x = c(2, 4, 1, 3, 3, 2)), .Names = "x", row.names = c("1",
> "2", "3", "4", "5", "6"), class = "data.frame")
>
> I want to recreate a new data frame whose rows are sum of (1&2, 3&4, 5&6)
> of original df. For example
>
> >newdf
>     x
> 1 6
> 2 4
> 3 5
>
> Thanx in advance for the help.
>
> Sachin
>
>
>
> ---------------------------------
>
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>
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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390 (Cell)
+1 513 247 0281 (Home)

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