Compare

d<-data.frame(a=c(1,2),b=c(2,3))
> class(d[,1])
[1] "numeric"
> class(d[,1,drop=FALSE])
[1] "data.frame"


Regards

On 20 Jun 2006 15:52:36 -0400, Allen S. Rout <asr@ufl.edu> wrote:
>
>
>
> I've observed something I don't understand, and I was hoping someone
> could point me to the right section of docs.
>
> There's a portion in one of my analyses in which I am wont to sort a
> data.frame so:
>
> seriesS  <- seriesS[order(as.Date(row.names(seriesS),format="%m/%d/%Y")),]
>
> So, I've got row.names which are textual representations of dates, I'd
> like to retain them as such, but order them datewise.
>
>
> As long as seriesS has more than one column, this works nicely,
> seriesS afterwards is a data.frame with columns similar to those it
> had going in.  But if I encounter a case with only one column, the
> result is _not_ a data frame, but instead an ? array? list?
>
> I can solve this with a kluge:
>
> seriesS$stupid <- 0;
> seriesS <- seriesS[order(as.Date(row.names(seriesS),format="%m/%d/%Y")),]
> seriesS <- seriesS[,-c(which(names(seriesS)=="stupid")) ]
>
> but this mostly tells me I've failed to understand something about how
> the process should work.
>
>
> Any good references to the Chapter and Verse of the Canon of R I
> should hit?
>
>
>
> - Allen S. Rout
>
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