Dear list
  
I want to obtain the adjusted r-square given a set of coefficients (without the intercept), and I don't know if there is a function that does it. Exist????????????????
I know that if you make a linear regression, you enter the dataset and have in "summary" the adjusted r-square. But this is calculated using the coefficients that R obtained,and I want other coefficients that i calculated separately and differently (without the intercept term too).
I have made a function based in the equations of the book "Linear Regression Analisys" (Wiley Series in probability and mathematical statistics), but it doesn't return values between 0 and 1. What is wrong????
The functions is given by:

                  
adjustedR2<-function(Y,X,saM) 
{
 if(is.matrix(Y)==F) (Y<-as.matrix(Y))    
 if(is.matrix(X)==F) (X<-as.matrix(X))    
 if(is.matrix(saM)==F) (saM<-as.matrix(saM))  
 RX<-rent.matrix(X,1)$Rentabilidade.tipo   
 RY<-rent.matrix(Y,1)$Rentabilidade.tipo   
 r2m<-matrix(0,nrow=ncol(Y),ncol=1)   
 RSS<-matrix(0,ncol=ncol(Y),nrow=1)   
 SYY<-matrix(0,ncol=ncol(Y),nrow=1)   
 for (i in 1:ncol(RY))    
 {    
    RSS[,i]<-(t(RY[,i])%*%RY[,i])-(saM[i,]%*%(t(RX)%*%RX)%*%t(saM)[,i])   
    SYY[,i]<-sum((RY[,i]-mean(RY[,i]))^2)    
    r2m[i,]<-1-(RSS[,i]/SYY[,i])*((nrow(RY))/(nrow(RY)-ncol(saM)-1))    
 }    
 dimnames(r2m)<-list(colnames(Y),c("Adjusted R-square"))  
 return(r2m) 
} 

  

  Thanks!
Alexandra



  Alexandra R. Mendes de Almeida

                                                 


		
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