Ah OK. That is probably it, though I can't see why.
 
In function sigma, I use a variable falled str, which would be bound in the environment to some value.
 
Then, in the sapply statment, I was hoping that by setting str to the values in the vector that is the first argument to sapply, I would get different plots each time I called lines afterwards with sigma. Do you see what I mean ?
 
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-----Original Message-----
From: jim holtman [mailto:jholtman@gmail.com]
Sent: 20 December 2005 19:20
To: Uzuner, Tolga
Subject: Re: [R] help with sapply, plot, lines


you are plotting the same line as originally over and over again.  what do you want to do with the parameters that you are passing in.  There is no call to sigma in the sapply.  How do you want to vary the parameters in the plot? 


On 12/20/05, Uzuner, Tolga < tolga.uzuner@csfb.com <mailto:tolga.uzuner@csfb.com> > wrote: 

Hi,

I am trying to plot multiple lines on a graph.

The function is particularly simple:

sigma<-function(lambda) atm-2*rr*(lambda-0.5)+16*str*(lambda-0.5)^2

which uses the variables atm, rr and str...

I define these as such:

atm<-0.4
rr<-0.2
str<-0.1


and this plots fine: 

plot(seq(0.01,0.99,0.01),sigma(seq(0.01,0.99,0.01)),ylim=c(0,1))

Now, I want to plot the same function for different values of str, as follows:

sapply(seq(0,0.3,0.05),function(s) {str<-s; lines(seq( 0.01,0.99,0.01),sigma(seq(0.01,0.99,0.01)))})

Hoping that sigma will lexically scope into str and that lines will appear on the same plot as the one I first drew above.

Instead, I just get this:
> sapply(seq(0, 0.3,0.05),function(s) {str<-s; lines(seq(0.01,0.99,0.01),sigma(seq(0.01,0.99,0.01)))})
[[1]]
NULL

[[2]]
NULL

[[3]]
NULL

[[4]]
NULL

[[5]]
NULL

[[6]]
NULL

[[7]] 
NULL

and the plot does not change.

Any assistance appreciated.

Regards,
Tolga








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What the problem you are trying to solve? 


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