Hi Ales, 
Thanks I had tried converting randgrpc previously to a factor 
- still didn't get the effect for the different groups.
Weird - do you think not getting different effects for each 
group might have to do with tidying up tmp files and the like?
I have had tmp file issues with well known commercial software.
Thanks
Regards
S.

________________________________

From: Ales Ziberna [mailto:aleszib@gmail.com]
Sent: Thu 24/11/2005 14:12
To: Stephen; r-help@stat.math.ethz.ch
Subject: Re: [R] Survreg Weibull lambda and p



Firstly, I assume that your variable is a numeric one. For seperat
values p
and lambda for diferent categories, you should convert it to factor.

However, this has no effect in your case, since you have only 2
categories.
You can have only one p and lambda for a variable with only 2 values.
The
model can only evaluate the diference, which is what you got, assuming
that
your groups are coded in such a way, that the difference between the
codes
is 1.

Best,
Ales Ziberna



----- Original Message -----
From: "Stephen" <szlevine@nana.co.il>
To: <r-help@stat.math.ethz.ch>
Sent: Thursday, November 24, 2005 10:13 AM
Subject: [R] Survreg Weibull lambda and p


> Hi All,
>
>
>
> I have conducted the following survival analysis which appears to be
OK
>
> (thanks BRipley for solving my earlier problem).
>
>
>
>> surv.mod1 <- survreg( Surv(timep1, relall6)~randgrpc, data=Dataset,
> dist="weibull", scale = 1)
>
>> summary(surv.mod1)
>
>
>
> Call:
>
> survreg(formula = Surv(timep1, relall6) ~ randgrpc, data = Dataset,
>
>    dist = "weibull", scale = 1)
>
>            Value Std. Error     z         p
>
> (Intercept)  7.36      0.259 28.42 1.27e-177
>
> randgrpc    -0.59      0.156 -3.80  1.47e-04
>
>
>
> Scale fixed at 1
>
>
>
> Weibull distribution
>
> Loglik(model)= -1268.6   Loglik(intercept only)= -1276
>
>        Chisq= 14.72 on 1 degrees of freedom, p= 0.00012
>
> Number of Newton-Raphson Iterations: 5
>
> n= 400
>
>
>
>> version
>
>         _
>
> platform i386-pc-mingw32
>
> arch     i386
>
> os       mingw32
>
> system   i386, mingw32
>
> status
>
> major    2
>
> minor    1.1
>
> year     2005
>
> month    06
>
> day      20
>
> language R
>
>>
>
> I emailed this output to a colleague and received an email requesting
> for the 2 groups (randgrpc in the code)
>
> the 'Weibull lambda and p values' in the analysis. I checked the
> mailings for direction but to no avail.
>
> Could someone please provide direction as how to extract the Weibull
> "lambda" and "p" for both randgrpc values?
>
> Many thanks
>
> S.
>
>
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>
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>
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