Hi All,

 

I have conducted the following survival analysis which appears to be OK 

(thanks BRipley for solving my earlier problem).

 

> surv.mod1 <- survreg( Surv(timep1, relall6)~randgrpc, data=Dataset,
dist="weibull", scale = 1)

> summary(surv.mod1)

 

Call:

survreg(formula = Surv(timep1, relall6) ~ randgrpc, data = Dataset, 

    dist = "weibull", scale = 1)

            Value Std. Error     z         p

(Intercept)  7.36      0.259 28.42 1.27e-177

randgrpc    -0.59      0.156 -3.80  1.47e-04

 

Scale fixed at 1 

 

Weibull distribution

Loglik(model)= -1268.6   Loglik(intercept only)= -1276

        Chisq= 14.72 on 1 degrees of freedom, p= 0.00012 

Number of Newton-Raphson Iterations: 5 

n= 400 

 

> version

         _              

platform i386-pc-mingw32

arch     i386           

os       mingw32        

system   i386, mingw32  

status                  

major    2              

minor    1.1            

year     2005           

month    06             

day      20             

language R              

>

I emailed this output to a colleague and received an email requesting
for the 2 groups (randgrpc in the code) 

the 'Weibull lambda and p values' in the analysis. I checked the
mailings for direction but to no avail. 

Could someone please provide direction as how to extract the Weibull
"lambda" and "p" for both randgrpc values? 

Many thanks

S.


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http://mail.nana.co.il

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