 Assuming that the data frame is called m, you can - split the data frame by the values of siteid and date- apply a function to create the new data frame for each such group and - use rbind to put it back together like this: fn &lt;- function(x) { y &lt;- t(x[,4:5]) data.frame( siteid=x[1,1], date=x[1,2], name=colnames(x)[4:5], x01=y[,1], x02=y[,2], x03=y[,3] )}m &lt;- do.call( "rbind", lapply(split(m,list(m$siteid,m$date)),fn) )If the order matters then add this line: m &lt;- m[ order(m$siteid,m$date), ]--- On Mon 09/29, &lt; Kang.Daiwen@epamail.epa.gov &gt; wrote:From: [mailto: Kang.Daiwen@epamail.epa.gov]To: r-help@stat.math.ethz.chDate: Mon, 29 Sep 2003 13:15:36 -0400Subject: [R] Data frame transposeHi All,I want to ask if there is a transpose function for data frame like theprocedure of transpose in SAS? Because I want to partially transpose adata frame which contains 5 columns (siteid, date, time, obs, mod), whatI want to do is to put time as the column variables along with siteid,and date, and put obs and mod in the row names. specifically totranspose a data frame:siteid date time obs modA 7/8 01 2 5A 7/8 02 3 8A 7/8 03 5 8A 7/9 01 3 6A 7/9 02 5 8A 7/9 03 6 7......B 7/8 01 4 7B 7/8 02 7 19B 7/8 03 4 9......Tositeid date name 01 02 03 ....A 7/8 obs 2 3 5A 7/8 mod 5 8 8A 7/9 obs 3 5 6A 7/9 mod 6 8 7.......B 7/8 obs 4 7 4B 7/8 mod 7 19 9........Thank you very much!Dave______________________________________________R-help@stat.math.ethz.ch mailing listhttps://www.stat.math.ethz.ch/mailman/listinfo/r-help

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