[R] Convert R object to a data frame

@vi@e@gross m@iii@g oii gm@ii@com @vi@e@gross m@iii@g oii gm@ii@com
Fri Jun 5 00:30:49 CEST 2026


It would help, John, if we understood what the resultant data.frame should look like.
The structure looks like it contains nested lists including a list of 4 containing 4 lists of 2. 

The contents range from int to num.

In a standard data.frame, you might want eight columns per row and would end up with four rows. 

You can now make data.frames CAREFULLY in which a column can contain something complex such as a list or the output of a statistical function. So, four columns each containing a list of 2 columns can be done.

Since you have a very specific data structure in mind, conversions could be straightforward or not.

Here is a simpleminded attempt to replicate your first structure to generate one row that unexpectedly does something a bit different:

myRow <-
  data.frame(
    alpha = list(criticalvalue=0.1, NumPeopleExposed=0),
    beta  = list(criticalvalue=0.2, NumPeopleExposed=0),
    gamma = list(criticalvalue=0.3, NumPeopleExposed=0),
    delta = list(criticalvalue=0.4, NumPeopleExposed=0)
  )

Note you could have initialized this from the other data structure by putting in references to those values instead of my constants BUT the goal was to see what it made and, well, it is not as expected:

> myRow
  alpha.criticalvalue alpha.NumPeopleExposed beta.criticalvalue beta.NumPeopleExposed gamma.criticalvalue
1                 0.1                      0                0.2                     0                 0.3
  gamma.NumPeopleExposed delta.criticalvalue delta.NumPeopleExposed
1                      0                 0.4                      0
> nrow(myRow)
[1] 1
> ncol(myRow)
[1] 8
> names(myRow)
[1] "alpha.criticalvalue"    "alpha.NumPeopleExposed" "beta.criticalvalue"     "beta.NumPeopleExposed" 
[5] "gamma.criticalvalue"    "gamma.NumPeopleExposed" "delta.criticalvalue"    "delta.NumPeopleExposed"

You need to protect a sub-list from base R with something like the I() function:

Is this version better?

myRow <-
  data.frame(
    alpha = I(list(criticalvalue=0.1, NumPeopleExposed=0)),
    beta  = I(list(criticalvalue=0.2, NumPeopleExposed=0)),
    gamma = I(list(criticalvalue=0.3, NumPeopleExposed=0)),
    delta = I(list(criticalvalue=0.4, NumPeopleExposed=0))
  )

> myRow
                 alpha beta gamma delta
criticalvalue      0.1  0.2   0.3   0.4
NumPeopleExposed     0    0     0     0
> nrow(myRow)
[1] 2
> ncol(myRow)
[1] 4
> names(myRow)
[1] "alpha" "beta"  "gamma" "delta"

Well, my one row now seems to be two rows with four per row.

> myRow$alpha
$criticalvalue
[1] 0.1

$NumPeopleExposed
[1] 0

> myRow$alpha$criticalvalue
[1] 0.1
> myRow$alpha$NumPeopleExposed
[1] 0

This seems to get you some of what you want. Something may be off as it should not be two rows.

I would suggest you can possibly find a solution in base R but my experience has been using various tidyverse functions as in dplyr to construct and use these embedded things.

Do note the above are examples of making a single row and as mentioned, you may want to combine multiple ones using various techniques such as rbind and cbind.





-----Original Message-----
From: R-help <r-help-bounces using r-project.org> On Behalf Of Rui Barradas via R-help
Sent: Thursday, June 4, 2026 5:19 PM
To: Sorkin, John <jsorkin using som.umaryland.edu>; R-help <r-help using r-project.org>
Subject: Re: [R] Convert R object to a data frame

Às 21:57 de 04/06/2026, Sorkin, John escreveu:
> I have an R object created lapply function within a by a by function
> 
>       results_by_date <- by(
>         data,
>          data[,"Date"],
>          function(subdata) {
>            lapply(
>            alertlevels,
>            check_cutpoints2,
>            data=subdata,
>            mycolumn=column
>            )
>          }
>       )
> 
> which has the following structure
> 
> $ 2020-08-14:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 0
>   $ 2020-08-15:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 1
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 0
>   $ 2020-08-16:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 15
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 6
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 6
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 6
>   $ 2020-08-17:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 58
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 20
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 7
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 2
>   $ 2020-08-18:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 79
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 45
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 16
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 6
>   $ 2020-08-19:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 187
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 100
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 61
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 38
>   $ 2020-08-20:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 121
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 31
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 13
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 4
>   $ 2020-08-21:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 17
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 8
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 5
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 3
>   $ 2020-08-22:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 35
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 12
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 6
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 2
>   $ 2020-08-23:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 32
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 15
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 8
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 4
>   $ 2020-08-24:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 15
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 5
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 1
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 0
>   $ 2020-08-25:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 43
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 26
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 13
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 5
>   $ 2020-08-26:List of 4
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.1
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.2
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.3
>    .. ..$ NumPeopleExposed: int 0
>    ..$ :List of 2
>    .. ..$ criticalvalue   : num 0.4
>    .. ..$ NumPeopleExposed: int 0
>   - attr(*, "dim")= int 13
>   - attr(*, "dimnames")=List of 1
>    ..$ data[, "Date"]: chr [1:13] "2020-08-14" "2020-08-15" "2020-08-16" "2020-08-17" ...
>   - attr(*, "call")= language by.data.frame(data = data, INDICES = data[, "Date"], FUN = function(subdata) {     lapply(alertlevels, check_cutp| __truncated__ ...
>   - attr(*, "class")= chr "by"
> NULL
> 
> I would like to convert the object to a dataframe. Can anyone suggest how I might accomplish this task?
> 
> Thank you,
> John
> 
> John David Sorkin M.D., Ph.D.
> Professor of Medicine, University of Maryland School of Medicine;
> Associate Director for Biostatistics and Informatics, Baltimore VA Medical Center Geriatrics Research, Education, and Clinical Center;
> Former PI Biostatistics and Informatics Core, University of Maryland School of Medicine Claude D. Pepper Older Americans Independence Center;
> Senior Statistician University of Maryland Center for Vascular Research;
> 
> Division of Gerontology, Geriatrics and Palliative Medicine,
> 10 North Greene Street
> GRECC (BT/18/GR)
> Baltimore, MD 21201-1524
> Cell phone 443-418-5382
> 
> 
> 
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
Hello,

The problem is that you have a lapply() nested in by(), so you will have 
to rbind twice.
It seems that


results_by_date <- by(
   data,
   data[,"Date"],
   function(subdata) {
     lapply(
       alertlevels,
       check_cutpoints2,
       data=subdata,
       mycolumn=column
     ) |> do.call(rbind, args = _)
   }
) |> do.call(rbind, args = _)


can solve it.
Can you post the output of dput(results_by_date[1:2]) ?

Hope this helps,

Rui Barradas

______________________________________________
R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



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