[R] Is there a sexy way ...?

[Bert Gunter]

Sorry, hit send by accident.
The 2-line version is:

x <- do.call(rbind, x)
dim(x) <- NULL

Cheers,
Bert

On Thu, Sep 26, 2024 at 9:23 PM Bert Gunter <bgunter.4567 using gmail.com> wrote:

> How about:
> as.vector(do.call(rbind,x))
>
> Cheers,
> Bert
>
>
>
>
> However, I much prefer a 2 line version:
>
> On Thu, Sep 26, 2024 at 8:56 PM Rolf Turner <rolfturner using posteo.net> wrote:
>
>>
>> I have (toy example):
>>
>> x <- list(`1` = c(7, 13, 1, 4, 10),
>>           `2` = c(2, 5,  14, 8, 11),
>>           `3` = c(6, 9, 15, 12, 3))
>> and
>>
>> f <- factor(rep(1:3,5))
>>
>> I want to create a vector v of length 15 such that the entries of v,
>> corresponding to level l of f are the entries of x[[l]].  I.e. I want
>> v to equal
>>
>>     c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3)
>>
>> I can create v "easily enough", using say, a for-loop.  It seems to me,
>> though, that there should be sexier (single command) way of achieving
>> the desired result.  However I cannot devise one.
>>
>> Can anyone point me in the right direction?  Thanks.
>>
>> cheers,
>>
>> Rolf Turner
>>
>> --
>> Honorary Research Fellow
>> Department of Statistics
>> University of Auckland
>> Stats. Dep't. (secretaries) phone:
>>          +64-9-373-7599 ext. 89622
>> Home phone: +64-9-480-4619
>>
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>>
>

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