[R] store list objects in data.table

[CALUM POLWART]

I think there is a typo in your reprex l(x^2) ??

mydt[1,2] contains a list. Which when unlisted contains a load of data.

I'm not sure what you are asking for? Are you trying to unlist that and
have it as a row? Sort of pivot.wider if you like or unnest in tidyverse
concepts?

I think the data.table verbs are rbindlist

But I haven't really understood what your end "product" looks like.

I think it's a two row table, with 20 intercepts and 20 gradients, repeated
a second time?

I'd have made that a 20 row table with x, y and then 4 columns for the two
versions?

On Sat, 21 Sep 2024, 22:25 Naresh Gurbuxani, <naresh_gurbuxani using hotmail.com>
wrote:

> I am trying to store regression objects in a data.table
>
> df <- data.frame(x = rnorm(20))
> df[, "y"] <- with(df, x + 0.1 * x^2 + 0.2 * rnorm(20))
>
> mydt <- data.table(mypower = c(1, 2), myreg = list(lm(y ~ x, data = df),
> lm(y ~ x + I(x^2), data = df)))
>
> mydt
> #   mypower    myreg
> #     <num>   <list>
> #1:       1 <lm[12]>
> #2:       2 <lm[12]>
>
> But mydt[1, 2] has only the coeffients of the first regression. mydt[2,
> 2] has residuals of the first regression.  These are the first two
> components of "lm" object.
>
> mydt[1, myreg[[1]]]
> #(Intercept)           x
> #   0.107245    1.034110
>
> Is there a way to put full "lm" object in each row?
>
> Thanks,
> Naresh
>
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