[R] R Processing dataframe by group - equivalent to SAS by group processing with a first. and retain statments
Jeff Newmiller
jdnewm|| @end|ng |rom dcn@d@v|@@c@@u@
Wed Nov 27 20:38:21 CET 2024
Was wondering when this would be suggested. But the question was about getting the final dataframe...
newdta <- olddta
newdta$FirstDay <- ave(newdata$date, newdata$ID, FUN = \(x) x[1L])
On November 27, 2024 11:13:49 AM PST, Rui Barradas <ruipbarradas using sapo.pt> wrote:
>Às 16:30 de 27/11/2024, Sorkin, John escreveu:
>> I am an old, long time SAS programmer. I need to produce R code that processes a dataframe in a manner that is equivalent to that produced by using a by statement in SAS and an if first.day statement and a retain statement:
>>
>> I want to take data (olddata) that looks like this
>> ID Day
>> 1 1
>> 1 1
>> 1 2
>> 1 2
>> 1 3
>> 1 3
>> 1 4
>> 1 4
>> 1 5
>> 1 5
>> 2 5
>> 2 5
>> 2 5
>> 2 6
>> 2 6
>> 2 6
>> 3 10
>> 3 10
>>
>> and make it look like this:
>> (withing each ID I am copying the first value of Day into a new variable, FirstDay, and propagating the FirstDay value through all rows that have the same ID:
>>
>> ID Day FirstDay
>> 1 1 1
>> 1 1 1
>> 1 2 1
>> 1 2 1
>> 1 3 1
>> 1 3 1
>> 1 4 1
>> 1 4 1
>> 1 5 1
>> 1 5 1
>> 2 5 5
>> 2 5 5
>> 2 5 5
>> 2 6 5
>> 2 6 5
>> 2 6 5
>> 3 10 3
>> 3 10 3
>>
>> SAS code that can do this is:
>>
>> proc sort data=olddata;
>> by ID Day;
>> run;
>>
>> data newdata;
>> retain FirstDay;
>> set olddata;
>> by ID;
>> if first.ID then FirstDay=Day;
>> run;
>>
>> I have NO idea how to do this is R (so I can't post test-code), but below I have R code that creates olddata:
>>
>> ID <- c(rep(1,10),rep(2,6),rep(3,2))
>> date <- c(rep(1,2),rep(2,2),rep(3,2),rep(4,2),rep(5,2),
>> rep(5,3),rep(6,3),rep(10,2))
>> date
>> olddata <- data.frame(ID=ID,date=date)
>> olddata
>>
>> Any suggestions on how to do this would be appreciated. . . I have worked on this for more than 12-hours, despite multiple we searches I have gotten nowhere. . .
>>
>> Thanks
>> John
>>
>>
>>
>>
>> John David Sorkin M.D., Ph.D.
>> Professor of Medicine, University of Maryland School of Medicine;
>> Associate Director for Biostatistics and Informatics, Baltimore VA Medical Center Geriatrics Research, Education, and Clinical Center;
>> PI Biostatistics and Informatics Core, University of Maryland School of Medicine Claude D. Pepper Older Americans Independence Center;
>> Senior Statistician University of Maryland Center for Vascular Research;
>>
>> Division of Gerontology and Paliative Care,
>> 10 North Greene Street
>> GRECC (BT/18/GR)
>> Baltimore, MD 21201-1524
>> Cell phone 443-418-5382
>>
>>
>>
>> ______________________________________________
>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>Hello,
>
>Isn't ?ave the simplest way?
>The first one-liner assumes the dates are sorted in ascending order.
>
>
>ave(olddata$date, olddata$ID, FUN = \(x) x[1L])
>#> [1] 1 1 1 1 1 1 1 1 1 1 5 5 5 5 5 5 10 10
>
>
>If the dates are not sorted,
>
>
>ave(olddata$date, olddata$ID, FUN = \(x) min(x))
>
>
>
>Hope this helps,
>
>Rui Barradas
>
>
--
Sent from my phone. Please excuse my brevity.
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