[R] add only the 1st of May with POSIXct

Wed May 29 13:17:08 CEST 2024

Às 07:01 de 29/05/2024, Stefano Sofia escreveu:
> Thank you Rui for your code.
> 
> I basically understood all your suggestions.
> 
> I am using an old version of R (version 3.6.3, installed in a server I am not allowed to control), and the new pipe operator does not work.
> 
> I tried to run your code without the "|>" operator, but I get an error when I use apply.
> 
> Could you please expand your code without the pipe operator?
> 
> 
> Thank you again for your help
> 
> Stefano
> 
> 
> 
>           (oo)
> --oOO--( )--OOo--------------------------------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy
> Meteo Section
> Snow Section
> Via del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
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> 
> ________________________________
> Da: Rui Barradas <ruipbarradas using sapo.pt>
> Inviato: martedì 28 maggio 2024 18:19
> A: Stefano Sofia; r-help using R-project.org
> Oggetto: Re: [R] add only the 1st of May with POSIXct
> 
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> Às 16:23 de 28/05/2024, Stefano Sofia escreveu:
>> Dear R-list users,
>>
>>   From an initial and a final date I create a sequence of days using POSIXct.
>>
>> If this interval covers all or only in part the months from May to October, I need to get rid of the days from the 2nd of May to the 31st of October:
>>
>>
>> a <- as.POSIXct("2002-11-01", format = "%Y-%m-%d", tz="Etc/GMT-1")
>>
>> b <- as.POSIXct("2004-06-01", format = "%Y-%m-%d", tz="Etc/GMT-1")
>>
>> mydf <- data.frame(data_POSIX=seq(as.POSIXct(paste(format(a, "%Y-%m-%d"), "09:00:00", sep=""), format="%Y-%m-%d %H:%M:%S", tz="Etc/GMT-1"), as.POSIXct(paste(format(b, "%Y-%m-%d"), "09:00:00", sep=""), format="%Y-%m-%d %H:%M:%S", tz="Etc/GMT-1"), by="1 day"))
>>
>>
>> If I execute
>>
>> as.data.frame(mydf[format(mydf$data_POSIX,"%m") %in% c("11", "12", "01", "02", "03", "04"), ])
>>
>> the interval will be
>>
>> from 2002-11-01 09:00:00 to 2003-04-30 09:00:00
>>
>> and from 2003-11-01 09:00:00 to 2004-04-30 09:00:00
>>
>>
>> but I need also 2003-05-01 09:00:00 and 2004-05-01 09:00:00
>>
>>
>> How can I solve this problem?
>>
>>
>> Thank you for your attention and your help
>>
>> Stefano
>>
>>
>>
>>            (oo)
>> --oOO--( )--OOo--------------------------------------
>> Stefano Sofia PhD
>> Civil Protection - Marche Region - Italy
>> Meteo Section
>> Snow Section
>> Via del Colle Ameno 5
>> 60126 Torrette di Ancona, Ancona (AN)
>> Uff: +39 071 806 7743
>> E-mail: stefano.sofia using regione.marche.it
>> ---Oo---------oO----------------------------------------
>>
>> ________________________________
>>
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>> and provide commented, minimal, self-contained, reproducible code.
> Hello,
> 
> First of all, 'a' and 'b' are already objects of class "POSIXct", you
> don't need to repeat the code creating them when creating mydf.
> 
> As for the question, see the code below.
> 
> 
> a <- as.POSIXct("2002-11-01", format = "%Y-%m-%d", tz="Etc/GMT-1")
> b <- as.POSIXct("2004-06-01", format = "%Y-%m-%d", tz="Etc/GMT-1")
> mydf <- data.frame(data_POSIX = seq(a, b, by = "1 day"))
> 
> # get the years from the data
> years <- format(c(a, b), "%Y") |> as.integer()
> # this creates a sequence with all the years
> years <- Reduce(`:`, years)
> 
> # coerce to "Date"
> from <- ISOdate(years, 5L, 2L, tz = "Etc/GMT-1")
> to <- ISOdate(years, 10L, 30L, tz = "Etc/GMT-1")
> 
> # this logical index keeps only the dates between May, 2nd and Nov 1st.
> keep <- data.frame(from, to) |>
>     apply(1L, \(x) x[1L] <= mydf$data_POSIX & mydf$data_POSIX <= x[2L]) |>
>     rowSums() > 0L
> 
> mydf[keep, , drop = FALSE]
> 
> 
> 
> Hope this helps,
> 
> Rui Barradas
> 
> 
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Hello,

Here is the code without the pipe operator.

years <- as.integer(format(c(a, b), "%Y") )
years <- Reduce(`:`, years)
from <- ISOdate(years, 5L, 2L, tz = "Etc/GMT-1")
to <- ISOdate(years, 10L, 30L, tz = "Etc/GMT-1")

keep <- apply(data.frame(from, to), 1L, \(x) x[1L] <= mydf$data_POSIX & 
mydf$data_POSIX <= x[2L])
keep <- rowSums(keep) > 0L

mydf[keep, , drop = FALSE]

R 3.6.3 was a long time ago (2020-02-29). Time to update R?

Hope this helps,

Rui Barradas