[R] Output of tapply function as data frame: Problem Fixed

Ogbos Okike g||ted|||e2014 @end|ng |rom gm@||@com
Fri Mar 29 02:43:05 CET 2024 

Dear Rui,
Thanks again for resolving this. I have already started using the version
that works for me.

But to clarify the second part, please let me paste the what I did and the
error message:

> set.seed(2024)
> data <- data.frame(
+    Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L,
+ TRUE),
+    count = sample(10L, 100L, TRUE)
+ )
>
> # coerce tapply's result to class "data.frame"
> res <- with(data, tapply(count, Date, mean)) |> as.data.frame()
Error: unexpected '>' in "res <- with(data, tapply(count, Date, mean)) |>"
> # assign a dates column from the row names
> res$Date <- row.names(res)
Error in row.names(res) : object 'res' not found
> # cosmetics
> names(res)[2:1] <- names(data)
Error in names(res)[2:1] <- names(data) : object 'res' not found
> # note that the row names are still tapply's names vector
> # and that the columns order is not Date/count. Both are fixed
> # after the calculations.
> res

You can see that the error message is on the pipe. Please, let me know
where I am missing it.
Thanks.

On Wed, Mar 27, 2024 at 10:45 PM Rui Barradas <ruipbarradas using sapo.pt> wrote:

> Às 08:58 de 27/03/2024, Ogbos Okike escreveu:
> > Dear Rui,
> > Nice to hear from you!
> >
> > I am sorry for the omission and I have taken note.
> >
> > Many thanks for responding. The second solution looks elegant as it
> quickly
> > resolved the problem.
> >
> > Please, take a second look at the first solution. It refused to run.
> Looks
> > as if the pipe is not properly positioned. Efforts to correct it and get
> it
> > run failed. If you can look further, it would be great. If time does not
> > permit, I am fine too.
> >
> > But having the too solutions will certainly make the subject more
> > interesting.
> > Thank you so much.
> > With warmest regards from
> > Ogbos
> >
> > On Wed, Mar 27, 2024 at 8:44 AM Rui Barradas <ruipbarradas using sapo.pt>
> wrote:
> >
> >> Às 04:30 de 27/03/2024, Ogbos Okike escreveu:
> >>> Warm greetings to you all.
> >>>
> >>> Using the tapply function below:
> >>> data<-read.table("FD1month",col.names = c("Dates","count"))
> >>> x=data$count
> >>>    f<-factor(data$Dates)
> >>> AB<- tapply(x,f,mean)
> >>>
> >>>
> >>> I made a simple calculation. The result, stored in AB, is of the form
> >>> below. But an effort to write AB to a file as a data frame fails. When
> I
> >>> use the write table, it only produces the count column and strip of the
> >>> first column (date).
> >>>
> >>> 2005-11-01 2005-12-01 2006-01-01 2006-02-01 2006-03-01 2006-04-01
> >>> 2006-05-01
> >>>    -4.106887  -4.259154  -5.836090  -4.756757  -4.118011  -4.487942
> >>>    -4.430705
> >>> 2006-06-01 2006-07-01 2006-08-01 2006-09-01 2006-10-01 2006-11-01
> >>> 2006-12-01
> >>>    -3.856727  -6.067103  -6.418767  -4.383031  -3.985805  -4.768196
> >>> -10.072579
> >>> 2007-01-01 2007-02-01 2007-03-01 2007-04-01 2007-05-01 2007-06-01
> >>> 2007-07-01
> >>>    -5.342338  -4.653128  -4.325094  -4.525373  -4.574783  -3.915600
> >>>    -4.127980
> >>> 2007-08-01 2007-09-01 2007-10-01 2007-11-01 2007-12-01 2008-01-01
> >>> 2008-02-01
> >>>    -3.952150  -4.033518  -4.532878  -4.522941  -4.485693  -3.922155
> >>>    -4.183578
> >>> 2008-03-01 2008-04-01 2008-05-01 2008-06-01 2008-07-01 2008-08-01
> >>> 2008-09-01
> >>>    -4.336969  -3.813306  -4.296579  -4.575095  -4.036036  -4.727994
> >>>    -4.347428
> >>> 2008-10-01 2008-11-01 2008-12-01
> >>>    -4.029918  -4.260326  -4.454224
> >>>
> >>> But the normal format I wish to display only appears on the terminal,
> >>> leading me to copy it and paste into a text file. That is, when I enter
> >> AB
> >>> on the terminal, it returns a format in the form:
> >>>
> >>> 008-02-01  -4.183578
> >>> 2008-03-01  -4.336969
> >>> 2008-04-01  -3.813306
> >>> 2008-05-01  -4.296579
> >>> 2008-06-01  -4.575095
> >>> 2008-07-01  -4.036036
> >>> 2008-08-01  -4.727994
> >>> 2008-09-01  -4.347428
> >>> 2008-10-01  -4.029918
> >>> 2008-11-01  -4.260326
> >>> 2008-12-01  -4.454224
> >>>
> >>> Now, my question: How do I write out two columns displayed by AB on the
> >>> terminal to a file?
> >>>
> >>> I have tried using AB<-data.frame(AB) but it doesn't work either.
> >>>
> >>> Many thanks for your time.
> >>> Ogbos
> >>>
> >>>        [[alternative HTML version deleted]]
> >>>
> >>> ______________________________________________
> >>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> >>> https://stat.ethz.ch/mailman/listinfo/r-help
> >>> PLEASE do read the posting guide
> >> http://www.R-project.org/posting-guide.html
> >>> and provide commented, minimal, self-contained, reproducible code.
> >> Hello,
> >>
> >> The main trick is to pipe to as.data.frame. But the result will have one
> >> column only, you must assign the dates from the df's row names.
> >> I also include an aggregate solution.
> >>
> >>
> >>
> >> # create a test data set
> >> set.seed(2024)
> >> data <- data.frame(
> >>     Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L,
> >> TRUE),
> >>     count = sample(10L, 100L, TRUE)
> >> )
> >>
> >> # coerce tapply's result to class "data.frame"
> >> res <- with(data, tapply(count, Date, mean)) |> as.data.frame()
> >> # assign a dates column from the row names
> >> res$Date <- row.names(res)
> >> # cosmetics
> >> names(res)[2:1] <- names(data)
> >> # note that the row names are still tapply's names vector
> >> # and that the columns order is not Date/count. Both are fixed
> >> # after the calculations.
> >> res
> >> #>               count       Date
> >> #> 2024-03-22 5.416667 2024-03-22
> >> #> 2024-03-23 5.500000 2024-03-23
> >> #> 2024-03-24 6.000000 2024-03-24
> >> #> 2024-03-25 4.476190 2024-03-25
> >> #> 2024-03-26 6.538462 2024-03-26
> >> #> 2024-03-27 5.200000 2024-03-27
> >>
> >> # fix the columns' order
> >> res <- res[2:1]
> >>
> >>
> >>
> >> # better all in one instruction
> >> aggregate(count ~ Date, data, mean)
> >> #>         Date    count
> >> #> 1 2024-03-22 5.416667
> >> #> 2 2024-03-23 5.500000
> >> #> 3 2024-03-24 6.000000
> >> #> 4 2024-03-25 4.476190
> >> #> 5 2024-03-26 6.538462
> >> #> 6 2024-03-27 5.200000
> >>
> >>
> >>
> >> Also,
> >> I'm glad to help as always but Ogbos, you have been an R-Help
> >> contributor for quite a while, please post data in dput format. Given
> >> the problem the output of the following is more than enough.
> >>
> >>
> >> dput(head(data, 20L))
> >>
> >>
> >> Hope this helps,
> >>
> >> Rui Barradas
> >>
> >>
> >> --
> >> Este e-mail foi analisado pelo software antivírus AVG para verificar a
> >> presença de vírus.
> >> www.avg.com
> >>
> >
> Hello,
>
> This pipe?
>
>
> with(data, tapply(count, Date, mean)) |> as.data.frame()
>
>
> I am not seeing anything wrong with it. I have tried it again just now
> and it runs with no problems, like it had before.
> A solution is not to pipe, separate the instructions.
>
>
> res <- with(data, tapply(count, Date, mean))
> res <- as.data.frame(res)
>
>
> But this should be equivalent to the pipe, I cannot think of a way to
> have this separated instructions run but not the pipe.
>
> Hope this helps,
>
> Rui Barradas
>
>
> --
> Este e-mail foi analisado pelo software antivírus AVG para verificar a
> presença de vírus.
> www.avg.com
>

	[[alternative HTML version deleted]]

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