[R] Reg: Help regarding ggplot2
Chris Evans
chr|@ho|d @end|ng |rom p@yctc@org
Tue May 2 11:37:43 CEST 2023
It's not clear what you want but ...
On 02/05/2023 10:57, Upananda Pani wrote:
> Dear All,
>
> I have a dataset which contains date and 12 other countries data. I
> have extracted the data as xts object.
>
> I am not able to recall all the series in the Y axis. My data set
> looks like this
>
> index crepub finland france germany italy netherlands norway poland
> <date> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
> 1 2005-01-03 1.21 0.615 1.90 3.01 0.346 0.509 1.05 1.13
> 2 2005-01-04 1.18 0.615 1.85 2.89 0.346 0.509 0.889 1.12
> 3 2005-01-05 1.15 0.615 1.81 2.78 0.346 0.509 0.785 1.09
> 4 2005-01-06 1.11 0.615 1.76 2.67 0.346 0.509 0.711 1.06
> 5 2005-01-07 1.08 0.615 1.72 2.57 0.346 0.509 0.661 1.02
> 6 2005-01-10 1.04 0.615 1.69 2.48 0.346 0.509 0.630 1.01
>
> My code for the same is as follows
>
> ggplot(data=data_vol3, aes(x=index, y=data_vol3$usa)+
> geom_line())
Well you don't need to say that the y data are from data_vol3, your data
= declaration says that.
I wonder if what you want is:
library(tidyverse)
tribble(
~rowN, ~index, ~crepub, ~finland, ~france, ~germany, ~italy,
~netherlands, ~norway, ~poland,
1, "2005-01-03", 1.21, 0.615, 1.90, 3.01, 0.346, 0.509, 1.05, 1.13,
2, "2005-01-04", 1.18, 0.615, 1.85, 2.89, 0.346, 0.509, 0.889, 1.12,
3, "2005-01-05", 1.15, 0.615, 1.81, 2.78, 0.346, 0.509, 0.785, 1.09,
4, "2005-01-06", 1.11, 0.615, 1.76, 2.67, 0.346, 0.509, 0.711, 1.06,
5, "2005-01-07", 1.08, 0.615, 1.72, 2.57, 0.346, 0.509, 0.661, 1.02,
6, "2005-01-10", 1.04, 0.615, 1.69, 2.48, 0.346, 0.509, 0.630, 1.01)
-> data_vol3
### please give us data using dput in future: saves us having to do
something like that to reclaim it!
### pivot that longer to make it easy to get country data as separate lines
data_vol3 %>% select(-rowN) %>%
pivot_longer(cols = -index, # as you want to pivot the other
variables/columns
names_to = "countries") -> tibDataVol3Long
ggplot(data = tibDataVol3Long,
aes(x = index, y = value,
### now get the grouping and use it for a colour legend
group = countries, colour = countries)) +
geom_line()
> Any help in this regard will be highly appreciated
>
> With regards,
> Upananda Pani
>
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--
Chris Evans (he/him)
Visiting Professor, UDLA, Quito, Ecuador & Honorary Professor,
University of Roehampton, London, UK.
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